- SATA disk = 80 IOPS
- SCSI DISK(SAS or FC) 10k RPM = 150 IOPS
- SCSI DISK(SAS or FC) 15k RPM = 180 IOPS
- SSD disk (SLC aka EFD) = 6000 IOPS
Here are most common RAID types used on standard disk arrays:
- RAID 0 - no redundancy, disk bundle, higest performance => WRITE PENALTY = 0
- RAID 1 - disk mirror, max bundle of 2 disks, high performance => WRITE PENALTY = 2
- RAID 10 - RAID 1 + RAID 0 for bundling disk pairs, max disk bundle depends on disk array limits, high performance => WRITE PENALTY = 2
- RAID 5 - block level striping with rotated parity, max disk bundle depends on disk array limits, moderate performance => WRITE PENALTY = 4
- RAID 6 - block level striping with double parity, max disk bundle depends on disk array limits, lower performance => WRITE PENALTY = 6
So performance from storage perspective and from host perspective are different. Performance from storage perspective is simply summation of speed of all disks in RAID group. Performance from host perspective depends on selected RAID type.
To calculate estimated storage performance from host perspective we need to use the formula of several variables.
First of all let's define variables
P=write penalty of selected RAID type
R=Read % of disk workload
W=Write % of disk workload
Do you want to know all steps how to get this formula? It is simple. Start from another formula which describes storage behavior.
R*(1*H) + W*(P*H) = S
Above formula says - each host read IOPS generates single storage IOPS but each write IOPS generates multiple IOPS based on RAID type penalty (P).
Does it make sense? If not example can help you to understand.
My RAID group has 9 SAS disks 600GB/15k RPM and I use RAID 5 (8+1).
So from storage perspective I have 9 disks where each can perform 180 IOPS which means I have performance 1620 IOPS from storage perspective. Let's assume I have strange read/write ratio 20:80.
S = 1620
P = 4 (because of RAID 5)
R = 20% = 0.2
W= 80% = 0.8
I need to know H ... storage performance from host perspective.
H = 1620 / (0.2 + 0.8 * 4) = 1620 / 3.4 = 476.47 IOPS from host perspective.
Note: Modern disk arrays often offer AST (Automated Storage Tiering). The calculation described in this blog post is valid even for those disk arrays. You have to fully understand internal architecture and design of particular storage but generally all storage pools are build from some sub disk groups bundled and protected by some RAID type. So if you have 125 disks bundled by 5 disks in RAID 5 (4+1) then the principle is the same. We have 125 spindles and write penalty is 4 because of RAID 5.